2017年8月28日 · Thus, we can create a sign diagram for x/ (x-3). This function will change signs at x=0 and x=3. Now, these two values divide the function domain into three areas, x<0, 0< x<3, and x>3. …

The answer is x in ]-oo, 0] uu [2, +oo [ Let s factorise the expression 4x^2-8x=4x (x-2) Let f (x)=4x (x-2) The domain of f (x) is D_f (x)=RR Now we can build the ...

The interval notation is ] -oo,-5 ] uu [-1,+oo [ Let's factorise the equation y=x^2+6x+5>=0 => (x+1) (x+5)>=0 Let's do a sign chart color (white) (aaaa)xcolor (white ...

The solution is x in ]-3,3/17] uu ]6,+oo [ As we cannot do crossing over, we need to rewrite the inequality (x-3)/ (x+3)<= (x+5)/ (x-6) (x-3)/ (x+3)- (x+5)/ (x-6)<=0 ...

Let #f (x) = x / (x^2+1)#, how do you use the first derivative test to determine which critical numbers, if any give relative extrema?

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