<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title>必应：H2O2</title><link>http://www.bing.com:80/search?q=H2O2</link><description>搜索结果</description><image><url>http://www.bing.com:80/s/a/rsslogo.gif</url><title>H2O2</title><link>http://www.bing.com:80/search?q=H2O2</link></image><copyright>版权所有 © 2026 Microsoft。保留所有权利。不得以任何方式或出于任何目的使用、复制或传输这些 XML 结果，除非出于个人的非商业用途在 RSS 聚合器中呈现必应结果。对这些结果的任何其他使用都需要获得 Microsoft Corporation 的明确书面许可。一经访问此网页或以任何方式使用这些结果，即表示您同意受上述限制的约束。</copyright><item><title>Why is H2O2 named hydrogen peroxide? - Chemistry Stack Exchange</title><link>https://chemistry.stackexchange.com/questions/53533/why-is-h2o2-named-hydrogen-peroxide</link><description>The structure of $\ce {H2O2}$ is $\ce {H-O-O-H}$, and an $\ce {- O-O -}$ functional group is called a peroxide, by definition. The peroxide functional group is attached to a hydrogen atom, so it's called hydrogen peroxide.</description><pubDate>周五, 03 4月 2026 21:15:00 GMT</pubDate></item><item><title>redox - Half equations for H2O2 for its reducing and oxidising nature ...</title><link>https://chemistry.stackexchange.com/questions/10375/half-equations-for-h2o2-for-its-reducing-and-oxidising-nature-in-acidic-and-alka</link><description>Is there a complete list of all the half equations for $\ce {H2O2}$ - both oxidation and reduction, in acidic and alkaline conditions? I've looked on the internet but can't seem to find a list with all of them.</description><pubDate>周日, 05 4月 2026 17:59:00 GMT</pubDate></item><item><title>inorganic chemistry - Reaction intermediates of MnO2 catalyzed H2O2 ...</title><link>https://chemistry.stackexchange.com/questions/7759/reaction-intermediates-of-mno2-catalyzed-h2o2-decomposition-reaction</link><description>Manganese dioxide catalyzes the decomposition of hydrogen peroxide to water and oxygen gas. But what are the intermediates in this catalyzed reaction?</description><pubDate>周六, 04 4月 2026 05:58:00 GMT</pubDate></item><item><title>How does KI catalyze the reaction with H2O2? - Chemistry Stack Exchange</title><link>https://chemistry.stackexchange.com/questions/171365/how-does-ki-catalyze-the-reaction-with-h2o2</link><description>The equations $ (1)$ and $ (21)$ shows that $\ce {H2O2}$ can undergo spontaneous self-oxidation-reduction, and is therefore, thermodynamically unstable. Accordingly, $\ce {H2O2}$ decomposes spontaneously and exothermically, but slowly to oxygen and water at room temperature.</description><pubDate>周六, 04 4月 2026 05:58:00 GMT</pubDate></item><item><title>Does H2O2 break down into H2O - Chemistry Stack Exchange</title><link>https://chemistry.stackexchange.com/questions/35869/does-h2o2-break-down-into-h2o-o-or-h2o-o2</link><description>$\ce {H2O2}$ will homolytically cleave for form two $\ce {.OH}$ radicals. Radicals are very reactive and will start a chain reaction, but ultimately you will end up with water and oxygen products from $\ce {H2O2}$. (Why does it form two hydroxy radicals? because the O-O single bond is weak and unstable - see MO theory) How do we know this?</description><pubDate>周四, 02 4月 2026 09:42:00 GMT</pubDate></item><item><title>What is the rate equation of decomposition of H2O2 with catalysts?</title><link>https://chemistry.stackexchange.com/questions/125517/what-is-the-rate-equation-of-decomposition-of-h2o2-with-catalysts</link><description>The decomposition of H2O2 is complex and has been the source of several studies. On iron oxide surface, here is a cited work `Catalytic Decomposition of Hydrogen Peroxide on Iron Oxide: Kinetics, Mechanism, and Implications’.</description><pubDate>周二, 31 3月 2026 14:52:00 GMT</pubDate></item><item><title>inorganic chemistry - What is the n factor of H2O2 undergoing ...</title><link>https://chemistry.stackexchange.com/questions/146793/what-is-the-n-factor-of-h2o2-undergoing-disproportionation-reaction-liberating-o</link><description>$$\ce {H2O2 + 2H+ + 2e → 2H2O}$$ Here 34.01 g of $\ce {H2O2}$ consumes two gram equivalents of hydrogen as an oxidizing agent. So the equivalent weight of this compound as an oxidizer in acidic medium is 34.01/2. The moral of the story is that normality is solely dependent on what reaction is being used!</description><pubDate>周三, 01 4月 2026 19:23:00 GMT</pubDate></item><item><title>The effects of H2o2 (hydrogen peroxide) with oils</title><link>https://chemistry.stackexchange.com/questions/57130/the-effects-of-h2o2-hydrogen-peroxide-with-oils</link><description>1 I have some 35% $\ce {H2O2}$ that I've been cutting down to 3% to create a product. Cheaper than buying pre cut solution from store. However, I've been thinking about trying to try it out with producing a new product which would induce mixing of the $\ce {H2O2}$ with pure oils and essential oils.</description><pubDate>周三, 01 4月 2026 20:27:00 GMT</pubDate></item><item><title>decomposition - Why and how does hydrogen peroxide decompose in the ...</title><link>https://chemistry.stackexchange.com/questions/116006/why-and-how-does-hydrogen-peroxide-decompose-in-the-presence-of-light</link><description>Like all other peroxides, hydrogen peroxide ($\ce {H2O2}$) also consists of a relatively weaker $\ce {O-O}$ bond, which is susceptible for light or heat. In the presence of light (the UV light from the sun catalyzes the reaction), $\ce {H2O2}$ spontaneously decomposes into water and oxygen.</description><pubDate>周四, 02 4月 2026 10:03:00 GMT</pubDate></item><item><title>catalysis - What is the "mechanism" of the decomposition of hydrogen ...</title><link>https://chemistry.stackexchange.com/questions/127385/what-is-the-mechanism-of-the-decomposition-of-hydrogen-peroxide</link><description>Below is one way to write it that shows what the enzyme does and avoids the uncertainty of the details: $$\ce {E + H2O2 -&gt; E-O + H2O}\tag {1}$$ $$\ce {E-O + H2O2 -&gt; E-O2 + H2O}\tag {2}$$ $$\ce {E-O2 -&gt; E + O2}\tag {3}$$ In words, the enzyme binds to the first molecule of hydrogen peroxide, release one molecule of water and holds on to the other oxygen atom (via the iron bound to heme bound to ...</description><pubDate>周四, 02 4月 2026 05:03:00 GMT</pubDate></item></channel></rss>